Codeforces Watermelon Solution in C & C++

Codeforces Watermelon Solution

4A. Watermelon Question

Introduction:

In this guide, we will take a deep dive into the Codeforces Watermelon Solution and provide you with a step-by-step approach to solve it. We will cover all the necessary details required to solve the problem with ease. Let’s get started!

Understanding the Problem:

The Codeforces solution 4A watermelon problem requires us to divide a watermelon of weight ‘w’ into two parts of equal weight, if possible. The weight of the watermelon ‘w’ is an even number ranging from 4 to 100.

Solving the Problem: To solve this problem, we can follow the steps below:

Step 1: Check if the weight of the watermelon is even or odd. If the weight is odd, we cannot divide it into two equal parts, and the answer is ‘NO’.

Step 2: If the weight is even, we can divide it into two equal parts. For example, if the weight is 8, we can divide it into two parts of weight 4 each.

Step 3: If the weight is even and greater than 2, we can always find two even numbers that add up to the weight of the watermelon. For example, if the weight is 10, we can divide it into two parts of weight 5 each by adding two even numbers 2 and 8.

Step 4: If the weight is even and less than or equal to 2, we cannot divide it into two equal parts, and the answer is ‘NO’.

Codeforces Watermelon Solution in C

#include<stdio.h>int main(){int w;scanf("%d",&w);if(w%2==0 && w>3){
printf("YES\n");
}
else{
printf("NO\n");
}return 0;}

Codeforces Watermelon Solution in C++

#include<iostream>
using namespace std;





int main(){
int w;





cin>>w;
if(w%2==0 && w>3)





{ cout<<"YES"<<endl;}

else{






cout<<"NO"<<endl;
}





return 0;
}

Conclusion:

In conclusion, we have provided a comprehensive guide to solve the Codeforces Solution 4A Watermelon problem. We have covered all the necessary steps required to solve the problem with ease. By following the steps mentioned above, you can easily solve the problem and get the desired output.

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