Beecrowd 1046 solution || URI – BEECROWD – BEE 1046 Solution in C, C++
Question
Game Time
Read the start time and end time of a game, in hours. Then calculate the duration of the game, knowing that the game can begin in a day and finish in another day, with a maximum duration of 24 hours. The message must be printed in portuguese “O JOGO DUROU X HORA(S)” that means “THE GAME LASTED X HOUR(S)”
Input
Two integer numbers representing the start and end time of a game.
Output
Print the duration of the game as in the sample output.Beecrowd 1046
| Input Sample | Output Sample |
| 16 2 | O JOGO DUROU 10 HORA(S) |
| 0 0 | O JOGO DUROU 24 HORA(S) |
| 2 16 | O JOGO DUROU 14 HORA(S) |
Beecrowd/Uri 1046 solution in C
#include <stdio.h>
int main() {
int a,b;
scanf("%d%d",&a,&b);
if(a==b){
printf("O JOGO DUROU 24 HORA(S)\n");
}
if(b>a){
printf("O JOGO DUROU %d HORA(S)\n",b-a);
}
if(a>b){
printf("O JOGO DUROU %d HORA(S)\n",(b+24)-a);//Beecrowd 1046 solution
}
return 0;
}
Beecrowd/Uri 1046 solution in C++
#include <iostream>
using namespace std;
int main() {
int a, b;
std::cin >> a >> b;
if (a == b) {
cout << "O JOGO DUROU 24 HORA(S)" <<endl;
} else if (b > a) {
cout << "O JOGO DUROU " << b - a << " HORA(S)" <<endl;
} else {
cout << "O JOGO DUROU " << (b + 24) - a << " HORA(S)" <<endl;
}
return 0;
}