Beecrowd 1178 Array Fill III Solution in C, C++|| Beecrowd 1178 || Free Code Center

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Beecrowd 1178 Array Fill III Solution in C, C++

Read a number X. Put this X at the first position of an array N [100]. In each subsequent position (1 up to 99) put half of the number inserted at the previous position, according to the example below. Print all the vector N.

Input

The input contains a double-precision number with four decimal places.

Output

For each position of the array N print “N[i] = Y”, where i is the array position and Y is the number stored in that position. Each number of N[…] must be printed with 4 digits after the decimal point.

Input Sample	Output Sample
200.0000	N[0] = 200.0000 N[1] = 100.0000 N[2] = 50.0000 N[3] = 25.0000 N[4] = 12.5000 …

Beecrowd 1178 Array Fill III Solution in C++

#include<iostream>
#include <iomanip>

using namespace std;
int main()
{
   double a;
   cin>>a;
   for(int i=0;i<100;i++){

               cout<<"N["<<i<<"] = "<<setprecision(4)<<fixed<<a<<endl;

         a=a/2.0;
             //  cout<<"N["<<i<<"]"<<setprecision(4)<<fixed<<a<<endl;


   }
   return 0;
}

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