## Beecrowd-1043 Triangle-solution ||Beecrowd 1043 solution

## Triangle

Read three-point floating values (A, B, and C) and verify if is possible to make a triangle with them. If it is possible, calculate the perimeter of the triangle and print the message:

Perimetro = XX.X

If it is not possible, calculate the area of the trapezium which basis A and B and C as height, and print the message:

Area = XX.X

**Input**

The input file has three floating point numbers.

**Output**

Print the result with one digit after the decimal point.

Input Sample | Output Sample |

6.0 4.0 2.0 | Area = 10.0 |

6.0 4.0 2.1 | Perimetro = 12.1 |

### Beecrowd -1043 Triangle Solution in C

#include<stdio.h> int main() { float a,b,c,area; scanf("%f%f%f",&a,&b,&c); if(a+b>c&&a+c>b&&b+c>a){ printf("Perimetro = %.1f\n",a+b+c); } else{ area =.5*(a+b)*c; printf("Area = %.1f\n",area); } return 0; }

### Beecrowd 1043 solution in C++

#include <iostream> using namespace std; int main() { float a, b, c, area; cin >> a >> b >> c; if(a + b > c && a + c > b && b + c > a){ cout << "Perimetro = " << a + b + c << endl; } else{ area = 0.5 * (a + b) * c; cout << "Area = " << area << endl; } return 0; }

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