Beecrowd 1026 To Carry Or Not To Carry Solution || Beecrowd 1026 Solution|| Free Code Center

Beecrowd 1026 To Carry or not to Carry Solution in C++

Introduction

URI/Beecrowd Online Judge is a platform that provides programming challenges and exercises to individuals who are interested in sharpening their programming skills. It is an excellent tool for anyone who wants to learn how to code, and the challenges are designed to be both challenging and engaging.

URI Beecrowd 1026 To Carry or Not to Carry Solution is one such programming challenge that is often attempted by C/C++ programmers. It involves bitwise operations, and the goal is to convert two integers to their binary form and then perform a bitwise XOR operation on them.

Problem Statement The problem statement for URI Beecrowd 1026 To Carry or not to Carry Solution is as follows:

“Read two integers and calculate the bitwise XOR between them. Then, convert this result to a decimal value.”

Solution in C++

#include <iostream>
using namespace std;

int main(){
 unsigned long int x, y, r;

 while(cin >> x >> y) {
      r = x ^ y;
     cout << r << endl;
 }

 return 0;
}