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Codeforces Solution

Way Too Long Words Codeforces solution in C++100% Accepted || Codeforces solution2023

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Way Too Long Words Codeforces solution in C++ is 100% Accepted.

Popular online venue Codeforces hosts fiercely competitive design contests. It helps programmers develop their problem-solving abilities by offering algorithmic tasks for them to solve. The section in Codeforces 71A labeled “Way Too Long Words” is one issue. We will look at the CPP solution to this issue in this article.

Codeforces -71A. Way Too Long Words question link

Understanding the issue

The unsettling message in “Way Too Long Words” is simple. It necessitates that we reduce terms that may be overly long due to specific circumstances. The entry consists of an integer ‘n’ followed by ‘n’ words. If the period of a word exceeds 10 characters, we want to update it with a new string that comprises the initial letter, the number of letters between the first and last letters (different), and the last letter.

Way Too Long Words Codeforces Solution in C++

#include<iostream>
#include<string>
using namespace std;
int main()
{
int n;
string s;
cin>>n;
for (int i=0;i>s;
int b=s.length();

 if(b>10)
   {
       cout<<s[0]<<b-2<<s[b-2]<<endl;//Way too long words solution
   }
   else
   {
       cout<<s<<endl;
   }
}
return 0; 
}

Next problem: Codeforces 1A. Theatre Square Solution in C/CPP

Codeforces Solution

Codeforces Watermelon Solution in C & C++

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Codeforces Watermelon Solution

4A. Watermelon Question

Introduction:

In this guide, we will take a deep dive into the Codeforces Watermelon Solution and provide you with a step-by-step approach to solve it. We will cover all the necessary details required to solve the problem with ease. Let’s get started!

Understanding the Problem:

The Codeforces solution 4A watermelon problem requires us to divide a watermelon of weight ‘w’ into two parts of equal weight, if possible. The weight of the watermelon ‘w’ is an even number ranging from 4 to 100.

Solving the Problem: To solve this problem, we can follow the steps below:

Step 1: Check if the weight of the watermelon is even or odd. If the weight is odd, we cannot divide it into two equal parts, and the answer is ‘NO’.

Step 2: If the weight is even, we can divide it into two equal parts. For example, if the weight is 8, we can divide it into two parts of weight 4 each.

Step 3: If the weight is even and greater than 2, we can always find two even numbers that add up to the weight of the watermelon. For example, if the weight is 10, we can divide it into two parts of weight 5 each by adding two even numbers 2 and 8.

Step 4: If the weight is even and less than or equal to 2, we cannot divide it into two equal parts, and the answer is ‘NO’.

Codeforces Watermelon Solution in C

#include<stdio.h>int main(){int w;scanf("%d",&w);if(w%2==0 && w>3){
printf("YES\n");
}
else{
printf("NO\n");
}return 0;}

Codeforces Watermelon Solution in C++

#include<iostream>
using namespace std;
int main(){
int w;
cin>>w;
if(w%2==0 && w>3)
{ cout<<"YES"<<endl;}


else{


cout<<"NO"<<endl;
}
return 0;
}

Conclusion:

In conclusion, we have provided a comprehensive guide to solve the Codeforces Solution 4A Watermelon problem. We have covered all the necessary steps required to solve the problem with ease. By following the steps mentioned above, you can easily solve the problem and get the desired output.

Next problem:Codeforces -71A. Way Too Long Words solution in CPP/C