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Codeforces 1807 B. Grab the Candies solution

problem question link

B. Grab the Candies

Mihai and Bianca are playing with bags of candies. They have a row a� of n� bags of candies. The i�-th bag has ai�� candies. The bags are given to the players in the order from the first bag to the n�-th bag.

If a bag has an even number of candies, Mihai grabs the bag. Otherwise, Bianca grabs the bag. Once a bag is grabbed, the number of candies in it gets added to the total number of candies of the player that took it.

Mihai wants to show off, so he wants to reorder the array so that at any moment (except at the start when they both have no candies), Mihai will have strictly more candies than Bianca. Help Mihai find out if such a reordering exists.

Input

The first line of the input contains an integer t� (1≤t≤10001≤�≤1000) — the number of test cases.

The first line of each test case contains a single integer n� (1≤n≤1001≤�≤100) — the number of bags in the array.

The second line of each test case contains n� space-separated integers ai�� (1≤ai≤1001≤��≤100) — the number of candies in each bag.

Output

For each test case, output “YES” (without quotes) if such a reordering exists, and “NO” (without quotes) otherwise.

You can output the answer in any case (for example, the strings “yEs”, “yes”, “Yes” and “YES” will be recognized as a positive answer)

INPUT:

3
4
1 2 3 4
4
1 1 1 2
3
1 4 3

OUTPUT :

YES
NO
NO

Codeforces 1807 B. Grab the Candies solution in C++

#include<iostream>
using namespace std;
int main()
{
    int a,n,c[101],b=0,m=0;
    cin>>a;
    for(int i=0;i<a;i++)
    {
        cin>>n;
        for(int j=0;j<n;j++)
        {
            cin>>c[j];
            if(c[j]%2==0)
            m+=c[j];
 
            else
                b+=c[j];
        }
         if(m>b)
    {
        cout<<"YES"<<endl;//Grab the Candies solution
    }
    else
        cout<<"NO"<<endl;
b=0;
m=0;
    }
 
}

Codeforces 1807 B. Grab the Candies solution in C

#include<stdio.h>

int main()
{
    int a, n, c[101], b = 0, m = 0;
    scanf("%d", &a);
    
    for (int i = 0; i < a; i++)
    {
        scanf("%d", &n);
        
        for (int j = 0; j < n; j++)
        {
            scanf("%d", &c[j]);
            
            if (c[j] % 2 == 0)
                m += c[j];
            else
                b += c[j];
        }
        
        if (m > b)
        {
            printf("YES\n"); // Grab the Candies solution
        }
        else
        {
            printf("NO\n");
        }
        
        b = 0;
        m = 0;
    }

    return 0;
}

Previous problem: Codeforces1807A. Plus or Minus(Div 4)

Codeforces1807A. Plus or Minus Solution

Codeforces1807A. Plus or Minus(Div 4)

Problem Question

In this guide, we will explore the A Plus or Minus problem, a classic problem in computer programming that requires you to calculate the sum of a series of integers, with each integer being either positive or negative. We will walk you through the process of solving this problem using Python, a popular programming language.Plus or Minus(Div 4)

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,b,c,n,s=0;
    cin>>n;
    for(int i=0;i<n;i++)
    {
        cin>>a>>b>>c;
        s=a+b;
        if(s==c) cout<<"+"<<endl;
        else cout<<"-"<<endl;
 
    }
}

Previous problem: Codeforces 110A. Nearly Lucky Number

BEECROWD Problems Solution

Robotic Process Automation

Robotic Process Automation
Robotic Process Automation

Robotic Process Automation presentation slides downbelow

What is Robotic Process Automation?

Robotic Process Automation (RPA) refers to the use of software bots to rule-based tasks within business processes. RPA is typically used to automate tasks such as data entry, invoice processing, customer service, and other back-office functions.

RPA bots can be programmed to perform a wide range of tasks, including navigating software applications, manipulating data, copying and pasting information, and even communicating with other systems or software robots. They can work 24/7, without breaks or errors, and can help companies save time and reduce costs associated with manual labor.

RPA is considered a type of “low-code” technology, meaning that it does not require extensive coding knowledge to set up and use. Instead, RPA tools use a visual interface and drag-and-drop functionality to create automation workflows.

How does RPA work?

RPA works by using software robots to automate repetitive, rules-based tasks that would normally be performed by humans. The robots are programmed to follow a set of predefined rules, which are typically based on the steps involved in a particular business process. Here’s a general overview of how RPA works:

1. Identify the process: First, the business process to be automated is identified. This could be anything from data entry and invoice processing to customer service and HR tasks.

2. Create a workflow: Next, a workflow is created that outlines the steps involved in the process. This workflow is typically created using a visual interface provided by the RPA software.

3. Program the bots: The RPA software is then used to program the software robots to perform each step in the workflow. This can involve tasks such as logging into software applications, copying and pasting data, and sending emails.

4. Monitor the bots: Once the bots have been programmed, they can be set to run automatically on a schedule or triggered by certain events. The RPA software also
provides monitoring tools that allow users to track the bots’ progress and identify any errors or issues.

5. Optimize the process: Finally, the RPA process can be optimized over time by analyzing data and making adjustments to the workflow and bot programming as needed. This helps to ensure that the process continues to run smoothly and efficiently.

The benefits of RPA

Robotic Process Automation (RPA) is a technology that uses software robots (bots) to automate repetitive, rules-based tasks, allowing employees to focus on more strategic and value-added activities. Here are some benefits of RPA:

  1. Increased efficiency: RPA can complete tasks faster and more accurately than humans, leading to increased efficiency and productivity. This allows employees to focus on more important tasks.
  2. Cost savings: Automating tasks with RPA can reduce the cost of labor, as well as the cost of errors and rework. RPA can also be implemented at a lower cost than traditional IT projects.
  3. Improved accuracy: RPA can reduce errors and improve accuracy, resulting in higher quality outputs and better customer experiences.
  4. Scalability: RPA can be easily scaled up or down depending on business needs, allowing organizations to quickly respond to changes in demand.
  5. Increased compliance: RPA can help organizations ensure compliance with regulations and policies by enforcing consistent processes and reducing the risk of errors.
  6. Improved employee satisfaction: By automating repetitive and mundane tasks, RPA can improve employee satisfaction and reduce burnout.
  7. Enhanced analytics: RPA can collect and analyze large amounts of data, providing insights that can help organizations make better decisions.

Overall, RPA can help organizations achieve operational excellence and drive business growth by streamlining processes, reducing costs, and improving quality and customer satisfaction.

Robotic Process Automation presentation slides

Downbelow

Robotic Process Automation

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Codeforces734A Anton and Danik solution

Codeforces734A Anton and Danik solution in Cpp

Question link

Codeforces734A Anton and Danik solution.

Anton likes to play chess, and so does his friend Danik.

Once they have played n games in a row. For each game, it’s known who was the winner — Anton or Danik. None of the games ended with a tie.

Now Anton wonders, who won more games, he or Danik? Help him determine this.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 100 000) — the number of games played.

The second line contains a string s, consisting of n uppercase English letters ‘A’ and ‘D’ — the outcome of each of the games. The i-th character of the string is equal to ‘A’ if the Anton won the i-th game and ‘D’ if Danik won the i-th game.

Output

If Anton won more games than Danik, print “Anton” (without quotes) in the only line of the output.

If Danik won more games than Anton, print “Danik” (without quotes) in the only line of the output.

If Anton and Danik won the same number of games, print “Friendship” (without quotes).

Examples

input

6
ADAAAA

output

Anton

solution in CPP:

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n,c=0,t=0;
    string a;
    cin>>n;
    cin>>a;
    for(int i=0;i<n;i++)
    {

        if(a[i]=='A') c++;
        else  t++;

    }
    if(c>t) cout<<"Anton"<<endl;
    else if(t>c) cout<<"Danik"<<endl;//Codeforces734A Anton and Danik solution
    else cout<<"Friendship"<<endl;
    }


Codeforces 110A. Nearly Lucky Number solution in CPP

Codeforces 110A Nearly Lucky Number Solution in CPP

Question link:

Codeforces 110A Nearly Lucky Number solution in CPP

#include<bits/stdc++.h>
using namespace std;
int main()
{
    string a;
    int c=0,z=0;

    cin>>a;
    for(int i=0;i<a.size();i++) {
        if(a[i]=='4'||a[i]=='7')//Codeforces 110A Nearly Lucky Number solution in CPP
            c++;

}
if(c==4||c==7)
  cout<<"YES"<<endl;
  else
      cout<<"NO"<<endl;
}


Codeforces 734A.Anton and Danik solution in Cpp

Codeforces 977A Wrong Subtraction solution in CPP

Question link:

Codeforces 977A Wrong Subtraction solution in CPP

Wrong Subtraction

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n,k,r=0;
    cin>>n>>k;
    for(int i=1;i<=k;i++) {

    r=n%10;
    if(r==0)
    {
        n/=10;
    }

       else
       {
           n=n-1;

    }
    }
    cout<<n;
}

Code Explanation

This is a C++ code that takes two integers n and k as input from the user, and then performs a loop that iterates k times. In each iteration, it does the following:

Calculate the remainder of n divided by 10 and store it in the variable r.
If r is equal to 0, divide n by 10.
Otherwise, subtract 1 from n.
After the loop finishes, the code prints the final value of n.    [Free Code Center]

The purpose of this code is to simulate a process where you can either divide a number by 10 (if it is divisible by 10), or subtract 1 from it, and repeat this process k times. The final value of n is the result of performing this process k times.Codeforces 977A Wrong Subtraction solution in CPP.codeforces problem solution .

For example, if n is 432 and k is 3, the first iteration of the loop will subtract 1 from n, since the remainder of 432 divided by 10 is not equal to 0. This will make n equal to 431. The second iteration will divide n by 10, making it equal to 43. The third iteration will also divide n by 10, making it equal to 4. Therefore, the final value of n will be 4.

Note that the bits/stdc++.h header file is not a standard C++ header file and is not guaranteed to be available on all compilers. It includes all standard library header files and some non-standard ones, and is commonly used in competitive programming. It is recommended to include only the necessary header files instead of relying on this non-standard header.
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Codeforces 110A Nearly Lucky Number Solution in CPP

Codeforces 59AWord Solution in C/CPP

Codeforces 59AWord Solution

question

Codeforces 59AWord Solution in CPP

#include<iostream>
#include<string>
#include<algorithm>
using namespace std;
int main()
{
    string a;
    int l=0,u=0;
    cin>>a;
    for(int i=0;i<a.size();i++)
    {
        if(a[i]>='a'&& a[i]<='z') {

            l++;
        }
        else
            u++;
    }
    if(l>=u){
        for(int i=0;i<a.size();i++)//Codeforces 59A.Word  Solution
            a[i]=tolower(a[i]);

        cout<<a<<endl;
    }
    else
    {
        for(int i=0;i<a.size();i++)
        {
            a[i]=toupper(a[i]);
        }
        cout<<a<<endl;
    }

}

Codeforces 59AWord Solution in C

#include <stdio.h>
#include <ctype.h>
#include <string.h>

#define MAX_SIZE 1000

int main()
{
    char a[MAX_SIZE];
    int l = 0, u = 0;
    scanf("%s", a);

    for (int i = 0; i < strlen(a); i++)
    {
        if (islower(a[i]))
        {
            l++;
        }
        else
        {
            u++;
        }
    }

    if (l >= u)
    {
        for (int i = 0; i < strlen(a); i++)
        {
            a[i] = tolower(a[i]);
        }
        printf("%s\n", a);
    }
    else
    {
        for (int i = 0; i < strlen(a); i++)
        {
            a[i] = toupper(a[i]);
        }
        printf("%s\n", a);
    }

    return 0;
}


Codeforces734A Anton and Danik solution

Elephant Codeforces || Codeforces 617A Elephant solution in C++

Codeforces Elephant Question

Elephant Codeforces solution in C++

An elephant decided to visit his friend. It turned out that the elephant’s house is located at point 0 and his friend’s house is located at point x(x > 0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend’s house.

Input

The first line of the input contains an integer x (1 ≤ x ≤ 1 000 000) — The coordinate of the friend’s house.

Output

Print the minimum number of steps that elephant needs to make to get from point 0 to point x.

Examples

input

5

output

1

Note

In the first sample the elephant needs to make one step of length 5 to reach the point x.

In the second sample the elephant can get to point x if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach x in less than three moves.

Elephant Codeforces solution in C++

#include<iostream>
using namespace std;
int main()
{
    int a,f=0;
    cin>>a;
    int d=0;
    if(a%5==0){
        cout<<a/5<<endl;
    }
    else {cout<<(a/5)+1<<endl;//Elephant Codeforces
 }
}

Previous problem Soldier and Bananas

Codeforces 546A Soldier and Bananas solution in C++

Codeforces 546A. Soldier and Bananas Question

A. Soldier and Bananas

A soldier wants to buy w bananas in the shop. He has to pay k dollars for the first banana, 2k dollars for the second one and so on (in other words, he has to pay i·k dollars for the i-th banana).

He has n dollars. How many dollars does he have to borrow from his friend soldier to buy w bananas?

Input

The first line contains three positive integers k, n, w (1  ≤  k, w  ≤  1000, 0 ≤ n ≤ 109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants.

Output

Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn’t have to borrow money, output 0.

Examples

input:
3  17  4
output:
13

Codeforces 546A Soldier and Bananas solution in C++

#include<iostream>
using namespace std;
int main()
{
    int w,k,z;
    long long int n;
    cin>>k>>n>>w;
    int sum=0;
    for(int i=1;i<=w;i++)
    {
        sum=sum+i;
    }
    int m=sum*k;
    int out=m-n;
    if(out<0)
    {
        cout<<"0"<<endl;
    }
    else{   
    cout<<out<<endl;}
}

Previous problem A. Bear and Big Brother

Stones On The Table Codeforces Solution || Codeforces 266A

Question

Stones on the Table Codeforces Solution in C++

Problem:There are n stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.

Input
The first line contains integer n (1 ≤ n ≤ 50) — the number of stones on the table.

The next line contains string s, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to n from left to right. Then the i-th character s equals "R", if the i-th stone is red, "G", if it's green and "B", if it's blue.

Output
Print a single integer — the answer to the problem.

Solution :

#include<iostream>
#include<string>
using namespace std;
int count;
int main()
{
    int a,i;
    cin>>a;
    string s;
    cin>>s;
    for(i=0;i<a;i++)
    {
    if(s[i]==s[i+1])
    {
        count++;
    }
 
    }
    cout<<count;//Stones On The Table Codeforces Solution
}

Codeforces 546A. Soldier and Bananas solution in C++