Bit++ Codeforces solution in c
Introduction
C programming is the foundation of modern software development. Whether you want to be a programmer or just want to expand your problem-solving skills, learning C will definitely empower you. Our step-by-step guide will take the mystery out of the process of creating a calculator, making it a fun and rewarding experience for you.
#include<stdio.h> int main() { int a,i; int x=0; char s[4]; scanf("%d",&a); for(i=0;i<a;i++){ scanf("%s",&s);//bit++ codeforces solution if(s[1]=='+'){ x++; } else { x--; } } printf("%d\n",x); return 0; }
Understanding the law
Before diving into the code, let’s understand its logic. The code snippet provided is a simple calculation of a series of input characters and performs addition (+) and subtraction (-) operations accordingly. The final result is then printed on the board.[bit++ codeforces solution in c]
How does a calculator work?
The calculator uses a loop to read the specified amount of input. Each input can be an addition or subtraction function. The variable x is increased for each addition, and x is decreased for each subtraction. The final value of x is the result of the numerator.
Let’s break the rules
include: This line includes the standard input/output library, which enables input and output operations in C .
int main(): The main function is the entry point for the function.
Two integer variables, int a, i;: a and i, are declared. which will contain the number of operations the user wants to perform.
int x = 0;: the variable x is initialized to zero, which will store the last result.
char s[4];: An s character set is designed to hold the input functions. The array size is set to 4 to accommodate operators and null terminations.
scanf(“%d”, &a);: Users are requested to enter the number of operations they want to run.
for(i = 0; i < a; i++): A for loop is used to iterate over a specified number of operations.
scanf(“%s”, &s);: The user is requested to enter a function as a string.
if(s[1] == ‘+’): The code checks that the second character of the s string is ‘+’, indicating one more event.
x++;: If the condition is true, x is incremented.
else: If the condition is false (i.e. subtraction operation).
x–;: x decreases.
printf(“%d\n”, x);: The last x value (result) is printed on the screen.//bit++ codeforces solution in c
return 0;: Special interest
Thanks for sharing. I read many of your blog posts, cool, your blog is very good.