Codeforces watermelon solution || a. watermelon codeforces solution || codeforces watermelon solution ||watermelon codeforces solution in python
we will follow the following step-wise approach to address this problem:
Step 1:- Know your Problem:-
The question: Can we divide a watermelon of fixed even weighting into two same-sized pieces where both parts are whole numbers? The weight of a watermelon is an even number again, and it must be between 4 to 100 kg. Iterative version. Constraints. If w is odd or there is no way to divide the weight perfectly such that both children get equal weights, then the answer should be “NO”.
Step 2: Check is Weight balanced or not
If the weight is odd, then you cannot distribute it equally between your two friends so that you will return NO. If not — print its weights divided into numbers two and n−1 where k≠0, therefore YES.
STEP 3: IF WEIGHT > 2
While the load is balanced, if it is equal to 2, we cannot split this into two parts with weight > 0, and hence, “NO” should be answered again. GET THE MOVER ON OTHERWISE IF38 SAMIXBUGA.
Step 4: Confirm the Division
If the watermelon has an even weight of over 2, you can easily divide it precisely into half. For example, if the weight is 8, we can split it as (4+4). So, in this instance, the answer is “YES”.”
There you go, Watermelon problem solved!
4A. Watermelon Question
Watermelon Solution in C
#include<stdio.h>
int main() {
int w;
scanf("%d", &w);
if (w % 2 == 0 && w > 3) {
printf("YES\n");
} else {
printf("NO\n");
}
return 0;
}
a.Watermelon Solution in C++
#include<iostream>
using namespace std;
int main() {
int w;
cin >> w;
if (w % 2 == 0 && w > 3) {
cout << "YES" << endl;
} else {
cout << "NO" << endl; // watermelon problem solution
}
return 0;
}
Watermelon Codeforces solution python
w = int(input())
if w % 2 == 0 and w > 3:
print("YES")
else:
print("NO") # watermelon problem solution
Conclusion:
We have gone through some of the steps needed to solve this with ease.
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