Beecrowd-1070 Six Odd Numbers Solution
Six Odd Number
Read an integer value X and print the 6 consecutive odd numbers from X, a value per line, including X if it is the case.
Input
The input will be a positive integer value.
Output
The output will be a sequence of six odd numbers.
| Input Sample | Output Sample |
| 8 | 9 11 13 15 17 19 |
Beecrowd 1070 Six Odd Numbers Solution in C
#include<stdio.h>
int main()
{
int x,i;
scanf("%d",&x);
if(x%2==0)x++;
for(i=0;i<6;i++){
printf("%d\n",x);
x=x+2;
}
return 0;
}
Solution in C++
#include<iostream>
using namespaces std;
int main()
{
int x;
cin>>x;
if(x%2==0)x++;
for(int i=0;i<6;i++)
{ cout<<x<<endl;
x=x+2;
}
return 0;
}
