Beecrowd 1015-Distance Between Two Points solution
Solution in C
#include<stdio.h>
int main(){
double x1,x2,y1,y2,d;
scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);
d=sqrt(pow(x2-x1,2)+pow(y2-y1,2));
printf("%.4lf\n",d);
return 0;
}
Solution in C++
#include <bits/stdc++.h>
using namespace std;
int main() {
double x1, x2, y1, y2, d;
cin >> x1 >> y1 >> x2 >> y2;
d = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
cout << fixed << setprecision(4) << d << endl;
return 0;
}
Solution in Python
import math
x1, y1, x2, y2 = map(float, input().split())
d = math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)
print(f"{d:.4f}")
very helpful
Can you be more specific about the content of your article? After reading it, I still have some doubts. Hope you can help me.